tells if a number is an hashard number or not

code/hashard.c

@@ -0,0 +1,29 @@
+#include <stdio.h>
+#include <stdlib.h>
+#include <string.h>
+#define n 10
+	int num,count,i,sum;
+	char buff[n];
+	int  a[n];
+ 	int main(){
+ 	
+ 	   printf("Enter a number: ");
+ 	   scanf("%d",&num);
+ 	   snprintf(buff,n,"%d\n",num);
+printf("%s\n",buff);
+count =strlen(buff)-1;
+printf("%d\n",count);
+snprintf(num,n,"%s\n",buff);
+ 	for(i=0;i<(count-1);i++){
+ 	 a[i] = buff[i];
+ 	}
+ 		for(i=0;i<(count-1);i++){
+ 	 	printf("%d\n",a[i]);
+ 	}
+
+         printf("A hashard num is one which is divisibe by the sum of its individual digits\n");
+         printf("e.g 27 is hashard bc 27/(2+7) = \"0\"\n");  
+   
+   return 0;      
+ 	}
+